Can the ideal gas law be used to explain the behavior of atmospheric gases?

... pressure? Answer. Using the ideal gas equation PV=nRT. 100ºC = 373K, R = 8.314, atmospheric pressure = 100 kPa. n = PV/RT= (100 x 24)/(8.314 x 373). n = 0.774 ... The volume (V) occupied by n moles of any gas has a pressure (P) at temperature (T) in Kelvin. (ie) P V = n R T, (R is known as the gas constant) is called ... ... T = 60 ° F = 60 + 460 = 520 ° R. Using Eq. (1.17): PV = n RT → 14.73 psi ⁎ 378.6 ft 3 = 1 ⁎ R ⁎ 520 → R = 14.37 ⁎ 378.6 520 = 10.732 psi ft 3 / pound − mole R. IDEAL GAS LAW: PV = nRT, where. P = pressure of the gas sample. V = volume of the gas sample. T = Kelvin temperature of the gas sample n = moles of the gas ... Jan 29, 2023 ... ... the Ideal Gas Law (PV = nRT) as: (nL)=(PRT). We know that Partial Pressure is directly proportional to Concentration: P=(nL)∗RT Pressure ... Answer and Explanation: 1 ... Here, P is the pressure of the gas, V is the volume of the gas, n is the number of moles of the gas, R is the universal gas constant ... PV = nRT. where P is the pressure, V is the volume, n is the number of moles of substance in that volume, R is a constant known as the "Universal Gas ... PV = nRT. Ideal ... n - Number of moles of gas. Remember, a mol of a substance is a unitless amount of particles of the substance. R - Ideal gas constant. where R is the specific gas constant. Specific gas constants in J/(kg K ... If the equation is rewritten as PV = nRT where n is the number of moles of gas. We know that n = 1, because we are trying to calculate the volume of 1 mole of gas. And, finally, R = 8.31441 J K-1 mol-1. Slotting all of this into the ...