The discriminant of a polynomial is nonzero if and only if the polynomial has distinct roots (over a separable closure). Can you explain why?

Let gcd(a, b, c) = 1, D = b 2 - 4ac. Then as remarked in Mathews ([4, pages 132--133]), then there exist integers #, # such that a# 2 + b## + c# 2 = a ... Jan 24, 2019 ... ... 2+bx+c=0 if and only if. x={-b± √{b2-4ac}}/{2a}. LaTeX Original \documentclass{article} \usepackage{amssymb, mathrsfs, enumitem} \usepackage ... Apr 7, 2014 ... I know how to derive the quadratic formula but not the alternate. -b ± √(b^2 - 4ac) b ± √(b^2 - 4ac) ... x1=(-b+sqrt(b^2-4ac))/2a=(-b+sqrt ... 2 Solving second-order polynomial equations. The roots of the following equation ax2 + bx + c = 0. (1) can be determined as: x1,2 = -b 소. / b2 - 4ac. 2a. (2). Aug 30, 2011 ... As a→0, √b2−4ac→|b|. If b>0, only the minus sign in the denominator makes sense, giving you 2c−2b=−cb. If b<0, only the plus sign in the ... If b2 – 4ac < 0, then the graph is an ellipse (if b = 0 and a = c, the graph is a circle). Let's investigate it! Open the Quadratic Equations applet: In the ... 2 )2 - b2. 4 + c. Quadratic formula: the roots of ax2 + bx + c are -b 소. /b2 - 4ac. 2a . Exponent rules: ab · ac = ab+c ab ac = ab−c. (ab)c = abc a1/b = b. - b Vb2-4ac. - b = Vb2-4ac. = b2- (b2-4ac). 2a(− b = √b² - 4ac hooray to writers who report and share something right! Howard Brand. Suitland High School. Oct 2, 2022 ... Find all the roots of the solution, and compute the distance between successive roots to see that it is a constant. If b2−4ac > 0 the equation has two distinct real number roots. Example. Study some of these examples: Find the roots of x2 +