In the context of multivariable polynomials, the hyperdiscriminant is more complex than a single scalar. Can you briefly describe this complexity?

Jan 5, 2022 ... (-12+√(b^2-4ac))/2a. (where a = 1, b = 5, c = 3). How do I write a ... Δ = b^2 - 4ac; x = (-b ± √Δ)/2a. And the most important one, in ... The quadratic formula, x=- b±sqrt(b^2-4ac)/2a, can be derived by completing the square on the general standard form a quadratic equation. Jan 24, 2019 ... ... 2+bx+c=0 if and only if. x={-b± √{b2-4ac}}/{2a}. LaTeX Original \documentclass{article} \usepackage{amssymb, mathrsfs, enumitem} \usepackage ... where a, b and c are real coefficients. The general solution to such an equation is given by the following formula, called the quadratic formula;. If b2 -4ac ... Let ax2 + bx + c = 0 be a quadratic equation with arbitrary coefficients a 6= 0, b and c. Its solution is given by the quadratic formula x1,2 = −b ±. √b2 − 4ac. s = (-b – [b2 – 4ac])/2a. 1. Add them: r + s = (-b + -b)/2a = -b/a. 2. Multiply them: rs = ([-b]2 – [b2 – 4ac])/4a2 = c/a. back. d=b2-4ac No solutions found Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : d-(b^2-4*a ... Simplify. Check the solutions. Using the Discriminant, b2 − 4ac, to Determine the Number and Type of Solutions of a Quadratic Equation. Jun 4, 2020 ... I wish I could use b^2-4ac>0 to check whether the people are real or not. Solve for a variable, factor, expand, evaluate fractions, linear equations, quadratic equations, inequalities, systems of equations, matrices.