How is the discriminant related to the fundamental theorem of algebra?

Jun 4, 2014 ... 3 Answers 3 ... Δ=b2−4ac>0 means that the equation has two real solutions. Δ=b2−4ac<0 means that the equation has no real solutions, but two ... Apr 11, 2018 ... For any equation of the form [ ax2 + bx + c = 0 ] the values of x ( the roots of the equation ) will always be [ ( -b ± ✓( b2 - 4ac ) ) / 2a ] ... Square root in the denominator ; − b {\displaystyle -b}. {\displaystyle -b} ; + b 2 − 4 a c {\displaystyle \textstyle +{\sqrt {b^{2}-4ac}}}. {\displaystyle \ ... ... 2 + q, the graph of y = f(x) has a turning point at (−p, q). • For the quadratic equation ax2 + bx + c = 0, the expression b2 – 4ac is called the discriminant. The solution depends on the value of b2 - 4ac. This term is called the "discriminant". There are three cases: If (b2 - 4ac) > 0.0, two real roots exist (i.e ... Jan 5, 2022 ... (-12+√(b^2-4ac))/2a. (where a = 1, b = 5, c = 3). How do I write a ... Δ = b^2 - 4ac; x = (-b ± √Δ)/2a. And the most important one, in ... where both square roots are to be considered when b2 − 4ac 6= 0,. (b) Use the result in part (a) to find the roots of the equation z2 + 2z + (1 − i) = 0. ) Suppose that a ~ 0 and that b2 — 4ac ≥ 0. Write the following number as an integer in standard form: ,_b_i/b2 —4ac\2. +b~. )+c. 2a. 2a. 0. Page 5. 6z4 —. 9z3 ... If b2 - 4ac is positive (>0) then we have 2 solutions. If b2 - 4ac is 0 then we have only one solution as the formula is reduced to x = [-b ± 0]/ ... Because the value of b2 – 4ac is less than zero, this equation will not have real solutions. Our answer will be 2x2 – 4x + 5 = 0. If we inspect all of the other ...