How is the discriminant related to the concept of algebraic independence?

- b Vb2-4ac. - b = Vb2-4ac. = b2- (b2-4ac). 2a(− b = √b² - 4ac hooray to writers who report and share something right! Howard Brand. Suitland High School. given the nature of the roots, to find the condition that makes this happen. Find the nature of the roots of 9x² +24x+16=0. a = 9 b=24 c = 16 b2-4ac ... b2 – 4ac < 0. No real roots. 4. b2 – 4ac = 32- 4x1x(-2) = 9 +8 = 17. b2 ... If b2 – 4ac < 0 , the line does not touch the curve. It is not a tangent. If ... Oct 20, 2011 ... (a) Prove that the discriminant D = b2 - 4ac ∈ K has a square root. /. D in L and that we have L = K(. /. D). [Hint: use the quadratic formula ... d=b2-4ac No solutions found Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : d-(b^2-4*a ... Jun 15, 2023 ... If the discriminant D < 0, then the quadratic equation ax 2 + bx + c = 0 will not have any real roots. Recall from precalcu- lus algebra that if the discriminant b2 - 4ac is positive, the equation (2) has two distinct ... 2 ) + b(c1y0. 1 + c2y0. 2) + c(c1y1 + ... b± b. 2 4ac. 2a. E= dV dx. F=q E. V = 1. 4. Q r. R. 2 =N a. 2 x. 2 =2 Dt c=6 R. = v R. Detailed step by step solution for k=(4ac-b^2)/(4a) Note: The number b2 - 4ac is called the discriminant of the equation ax2 + bx + c = 0. If the discriminant is negative then the equation has no real solutions.