Are there any applications of the discriminant in mathematical physics, such as in string theory or quantum mechanics?

Mar 4, 2018 ... Explanation: · ⇒ · + · + · 1 · = · 0 · ← · in standard form. with a=2,b=3 and c=1. ⇒b2−4a ... The answer is statement 1 only, which would be selection A. A graph that meets the criteria expressed above would be: -x^2 + x - 1. (Algebra: solve quadratic equations) The two roots of a quadratic equation ax^2 + bx + c = 0 can be obtained using the following formula: b^2 - 4ac is ... Apr 7, 2014 ... I know how to derive the quadratic formula but not the alternate. -b ± √(b^2 - 4ac) b ± √(b^2 - 4ac) ... x1=(-b+sqrt(b^2-4ac))/2a=(-b+sqrt ... Solve for a variable, factor, expand, evaluate fractions, linear equations, quadratic equations, inequalities, systems of equations, matrices. The solution depends on the value of b2 - 4ac. This term is called the "discriminant". There are three cases: If (b2 - 4ac) > 0.0, two real roots exist (i.e ... (2ax + b)2 = b2 − 4ac. ⇒. 2ax + b = ±. √ b2 − 4ac. ⇒. 2ax = −b ±. √ b2 − 4ac. ⇒ x = −b±. √ b2−4ac. 2a . This is the quadratic formula. 1Jason Zimba is a ... b2 − 4ac = (−5)2 − 4 × 1 × 6=1 therefore, there are two solutions. Solution: Question 1 (continued). Substituting into the quadratic formula gives: x = −b ... F(z/Va- -b/2a) satisfies. (2) G(z)G(z + 1) = G(z2 + z - d), where d = (b2 - 4ac)/4a. The set Sd of roots of the polynomial G (z) is a finite nonempty set of ... 2 Solving second-order polynomial equations. The roots of the following equation ax2 + bx + c = 0. (1) can be determined as: x1,2 = -b 소. / b2 - 4ac. 2a. (2).